A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.
For example, [1,7,4,9,2,5]
is a wiggle sequence because the differences (6,-3,5,-7,3) are alternately positive and negative. In contrast, [1,4,7,2,5]
and [1,7,4,5,5]
are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.
Examples:
Input: [1,7,4,9,2,5] Output: 6 The entire sequence is a wiggle sequence. Input: [1,17,5,10,13,15,10,5,16,8] Output: 7 There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8]. Input: [1,2,3,4,5,6,7,8,9] Output: 2
Follow up:
Can you do it in O(n) time?
简单点就是求构成跌宕起伏、波动的数的最大数目。
只要前后波动变化就就加一,然后就没然后了,循环计算判断就好了。
设置一个flag表示前面的波动,0表示开始或开始时没有波动、-1表示向下波动、1表示向上波动,
class Solution {
public:
int wiggleMaxLength(vector<int>& nums) {
int len = nums.size();
if(len < 1){
return 0;
}
int flag =0;
int count=1;
for(int i=1; i<len; i++){
if(nums[i] - nums[i-1] > 0){
if(flag == 0 || flag == -1){
count++;
}
flag = 1;
}
else if(nums[i] - nums[i-1] < 0){
if(flag == 0 || flag == 1){
count++;
}
flag = -1;
}
}
return count;
}
};