class Solution(object):
def reverseList(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
cur, pre = head, None
while cur:
cur.next, pre, cur = pre, cur, cur.next
return pre
【LeetCode】206. Reverse Linked List
最新推荐文章于 2023-04-22 14:43:50 发布