/*
编写一个程序,定义抽象基类Shape,由它派生出5个派生类: Circle(圆形)、Square(正方形)、Rectangle(矩形)、Trapezoid(梯形)、Triangle(三角形)。
用虚函数分别计算几种图形面积,并求它们之和。
要求用基类指针数组,使它每一个元素指向一个派生类对象。
Input
圆的半径
正方形的边长
矩形的边长
梯形的上底和下底,高
三角形的底与高
Output
所有图形面积之和(结果保留两位小数)
*/
#include <iostream>
#include <iomanip>
#define PI 3.1415926
using namespace std;
class Shape
{
public:
virtual double area()=0;
};
class Circle:public Shape//(圆形)
{
public:
Circle():Shape(){}
Circle(double a):r(a){}
double area()
{
return r*r*PI;
}
private:
double r;
};
class Rectangle:public Shape//(矩形)
{
public:
Rectangle():Shape(){}
Rectangle(double a,double b):l(a),m(b){}
double area()
{
return l*m;
}
private:
double l;
double m;
};
class Triangle:public Shape//(三角形)
{
public:
Triangle():Shape(){}
Triangle(double a,double b):y(a),n(b){}
double area()
{
return (y*n)/2;
}
private:
double y;
double n;
};
class Square:public Shape//Square(正方形)
{
public:
Square():Shape(){}
Square(double c):m(c){}
double area()
{
return m*m;
}
private:
double m;
};
class Trapezoid:public Shape//Trapezoid(梯形)
{
public:
Trapezoid():Shape(){}
Trapezoid(double c,double g,double h):i(c),o(g),p(h){}
double area()
{
return ((i+o)*p)/2;
}
private:
double i;
double o;
double p;
};
int main()
{
float r,a,b,w1,w2,w,h;
cout<<fixed<<setprecision(2);
cin>>r;
Circle circle(r);
cin>>a;
Square square(a);
cin>>a>>b;
Rectangle rectangle(a,b);
cin>>w1>>w2>>h;
Trapezoid trapezoid(w1,w1,h);
cin>>w>>h;
Triangle triangle(w,h);
Shape *pt[5]= {&circle,&square,&rectangle,&trapezoid,&triangle};
double areas=0.0;
for(int i=0; i<5; i++)
areas=areas+pt[i]->area();
cout<<"total of all areas="<<areas<<endl;
return 0;
}
OJ 1.H
最新推荐文章于 2021-06-24 16:28:20 发布