Problem:
Given two strings s and t, determine if they are isomorphic.
Two strings are isomorphic if the characters in s can be replaced to get t.
All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.
For example,
Given "egg"
, "add"
,
return true.
Given "foo"
, "bar"
,
return false.
Given "paper"
, "title"
,
return true.
Analysis:
Solutions:
C++:
bool isIsomorphic(string s, string t) {
if(s.size() != t.size())
return false;
if(s.empty() && t.empty())
return true;
map<char, char> map_s_to_t;
bool map_t_to_s[256] = {false};
int size = s.size();
for(int i = 0; i < size; ++i) {
if(map_s_to_t.find(s[i]) == map_s_to_t.end()) {
if(map_t_to_s[int(t[i])])
return false;
map_s_to_t[int(s[i])] = int(t[i]);
map_t_to_s[int(t[i])] = true;
} else {
if(t[i] != map_s_to_t[s[i]])
return false;
}
}
return true;
}
Java:
Python: