Golang保存xml文件

目录

1 保存xml

2 保存文件名

 3 控制台输出

---

1 保存xml

package main

import (
	"encoding/xml"
	"fmt"
	"os"
)

type Servers struct {
	XMLName xml.Name       `xml:"servers"`
	Version string         `xml:"version,attr"`
	Server  []singleServer `xml:"server"`
}

type singleServer struct {
	ServerName string `xml:"serverName"`
	ServerIP   string `xml:"serverIP"`
}

func main() {
	servers := Servers{}

	servers.Version = "1"
	servers.Server = append(servers.Server, singleServer{"Local_webd", "127.0.0.1"})
	servers.Server = append(servers.Server, singleServer{"Local_DBd", "127.0.0.2"})
	indent, err := xml.MarshalIndent(servers, " ", "  ")
	if err != nil {
		fmt.Println("error:%v\n", err)
		return
	}

	// 保存为文件
	create, err := os.Create("Server.xml")
	if err != nil {
		return
	}

	// xml头
	create.Write([]byte(xml.Header))
	create.Write(indent)

	// 要延时关闭文件流
	defer create.Close()

	// 控制台输出
	os.Stdout.Write([]byte(xml.Header))
	os.Stdout.Write(indent)
}

2 保存文件名

 3 控制台输出

<?xml version="1.0" encoding="UTF-8"?>
 <servers version="1">
   <server>
     <serverName>Local_webd</serverName>
     <serverIP>127.0.0.1</serverIP>
   </server>
   <server>
     <serverName>Local_DBd</serverName>
     <serverIP>127.0.0.2</serverIP>
   </server>
 </servers>