cf——A. The Great Game

本文介绍了一种通过分析两个队伍的动作来决定游戏世界冠军的方法。输入包含两串字符,分别代表两个队伍的动作,通过比较这些动作来判断胜负。文章提供了一个示例性的代码实现。

Two teams meet in The Game World Championship. Some scientists consider this game to be the most intellectually challenging game in the world. You are given two strings describing the teams' actions in the final battle. Figure out who became the champion.

Input

The input contains two strings of equal length (between 2 and 20 characters, inclusive). Each line describes the actions of one team.

Output

Output "TEAM 1 WINS" if the first team won, "TEAM 2 WINS" if the second team won, and "TIE" if there was a tie.

题意:[]代表布,()代表石头,8<代表剪刀

输出哪个队赢

Sample test(s)
input
[]()[]8<
8<[]()8<
output
TEAM 2 WINS
input
8<8<()
[]8<[]
output
TIE
#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
int main()
{
    string s1,s2;
    cin>>s1;
    cin>>s2;
    int count1=0,count2=0;
    for(int i=0;i<s1.size();i+=2)
    {
        if(s1[i]==s2[i])
        {
            count1++;
            count2++;
        }
        else if(s1[i]=='8'&&s2[i]!='8')
        {
            if(s2[i]=='[')
            count1++;
            else if(s2[i]=='(')
            count2++;
        }
        else if(s1[i]=='['&&s2[i]!='[')
        {
            if(s2[i]=='8')
            count2++;
            else if(s2[i]=='(')
            count1++;
        }
        else if(s1[i]=='('&&s2[i]!='(')
        {
            if(s2[i]=='8')
            count1++;
            else if(s2[i]=='[')
            count2++;
        }
    }
    if(count1>count2)
    cout<<"TEAM 1 WINS"<<endl;
    else if(count1<count2)
    cout<<"TEAM 2 WINS"<<endl;
    else
    cout<<"TIE"<<endl;
    return 0;
}

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值