求a-z26个字母的三三组合

#include <stdio.h>


int bit(unsigned int x)                //求一个数比特位为1的个数
{
int c = 0;


while( x )
{
c++;


x = (x & (x - 1));
}

return c;
}


void print(unsigned int x, int count)
{
int i = 0;


if( bit(x) == count )
{
for(i=0; i<26; i++)
{
if( x & 1)
{
printf("%c ", (char)('a' + i));
}


x = (x >> 1);
}
    
printf("\n");
}
}


int main()
{
    const unsigned int N = 26;
    const unsigned int C = 3;
    
const unsigned int X = (1 << N) - 1;
unsigned int i = 0;

for(i=0; i<X; i++)
{
print(i, C);
}


return 0;
   
}