加菲猫爱上紫罗兰 的专栏

演示C++在构造函数中抛出异常时，不调用析构函数，导致资源不能释放的一种解决方法。   namespace TEST {     void exception()     {         class A         {         public:             A()             {                 cout        

DALXmlFile.h： #ifndef DALXMLFILE_H_INCLUDED #define DALXMLFILE_H_INCLUDED #include "rapidxml.hpp" #include "rapidxml_utils.hpp" #include "rapidxml_print.hpp" ///a wrapper for xml file. c

#include #include using namespace std;class requirement { public:     requirement(requirement* _rq,int _level)         :rq(_rq),level(_level)     {    }    //virtual setLevel(requirement* rq, i

#include #include using namespace std;class simpledb { public:     simpledb()     {         }     simpledb(string dbname)     {         db_name = dbname;     }    void state()     {     

#include #include using namespace std; class numContext { public:     void show(int val)     {         cout"num  = "valendl;     } }; class numExp { public:     numExp()     {     }