python 内建函数 range map reduce sorted set

1.range

list=[x**2 for x in range(0,11,2)]
print(list)#[0, 4, 16, 36, 64, 100]

#列表生成式
l2=(x**2 for x in range(0,11,2))
print(type(l2))#<class 'generator'>
print(next(l2))#0
print(next(l2))#4
print(next(l2))#16

2.map

'''
map
function -- 函数
iterable -- 一个或多个序列
'''
l3=map(lambda x : x +3,[1,2,5,8])
for temp in l3:
    print("--%s"%temp)


l4=map(lambda x,y:x+y,[1,3,5],[2,4,6])
for temp in l4:
    print("---%s" % temp)

3.reduce

from functools import reduce
r1=reduce(lambda x,y:x+y,[1,2,3,4])
print(r1)#10
r1=reduce(lambda x,y:x+y,[1,2,3,4],5)
print(r1)#15
r1=reduce(lambda x,y:x+y,["aa","bb","cc"],"dd")
print(r1)#ddaabbcc

4.sorted

ll=[2,323,424,323,4,55,366,24323,23254,265646]
#排序
print(sorted(ll))
#[2, 4, 55, 323, 323, 366, 424, 23254, 24323, 265646]
#反排序
print(sorted(ll,reverse=1))
#[265646, 24323, 23254, 424, 366, 323, 323, 55, 4, 2]

5set

l=['aa','bb','aa','ca','ac','bb','aa']
print(set(l))#列表去掉重复 {'ac', 'ca', 'bb', 'aa'} 注意：去掉重复后 转换成集合
print(list(set(l)))#['ac', 'ca', 'bb', 'aa'] 集合转化成 列表

a={'a',"aa","cc","c"}
b={"aaa","aa","b","cc"}
print(a&b)#{'aa', 'cc'}
print(a|b)#{'a', 'b', 'aaa', 'aa', 'cc', 'c'}
print(a-b)#差集 {'c', 'a'}
print(a^b)#对称差集 {'b', 'aaa', 'c', 'a'}