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UVA 10494 (13.08.02)
点此连接到UVA10494思路: 采取一种, 边取余边取整的方法, 让这题变的简单许多~AC代码:#include#includeint main() { long long mod; long long k, tmp; int len; int ans[10010]; char num[10010], ch[2]; while(scanf("%s%s%l原创 2013-08-02 20:30:02 · 915 阅读 · 0 评论 -
UVA 465 (13.08.02)
Overflow Write a program that reads an expression consisting of twonon-negative integer and an operator. Determine if either integer orthe result of the expression is too large to be repre原创 2013-08-02 20:22:20 · 880 阅读 · 0 评论 -
HDU 1013 (13.10.29)
Problem DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resultin原创 2013-10-30 00:47:42 · 1094 阅读 · 0 评论 -
UVA 424 (大树相加 13.08.02)
Integer Inquiry One of the first users of BIT's new supercomputer was Chip Diller. Heextended his explorationof powers of 3 to go from 0 to 333 and he explored taking various sumsof those原创 2013-08-02 20:06:25 · 1079 阅读 · 0 评论 -
UVA 10106 (大数相乘 13.08.02)
Product The ProblemThe problem is to multiply two integers X, Y. (0250)The InputThe input will consist of a set of pairs of lines. Each line in pair contains one multiplyer.The O原创 2013-08-02 20:08:39 · 924 阅读 · 0 评论