题目:
Reverse bits of a given 32 bits unsigned integer.
For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).
Follow up:
If this function is called many times, how would you optimize it?
Related problem: Reverse Integer
分析:
一开始习惯性写int,后来WA之后测试才发现应该写uint32_t,总之以后不能出现这种错误了。
代码:
class Solution {
public:
uint32_t reverseBits(uint32_t n) {
uint32_t res=0;
uint32_t resTmp=pow(2,31);
while(n){
if(n%2)res+=resTmp;
n/=2;
resTmp/=2;
}
return res;
}
};