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poj1579
Function Run Fun Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 12713 Accepted: 6621 Description We all love recursion! Don't we? Consider a three-p原创 2012-06-06 19:52:41 · 547 阅读 · 0 评论 -
poj 1953 World Cup Noise
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 13552 Accepted: 6703 Description Background "KO-RE-A, KO-RE-A" shout 54.000 happy football fan原创 2012-10-15 20:36:50 · 511 阅读 · 0 评论 -
poj 水题
1000 纯属适应题 1003 做的时候花了很久,现在看好像也不难 1004 适应题,求下平均就行 1005 要读懂题就行 1007 逆序数,discuss方法 1046 全部暴搜一遍。。 1118 照抄2606没看题。。WA。。RE全占了 1207 貌似我的方法超级麻烦 1247 读懂题目比较麻烦 1248 暴力过的。。 1250 一整个晚上整这一道题。原创 2012-11-13 20:35:02 · 471 阅读 · 0 评论 -
poj1477
#include int main (){ int al,num,i,n,m=1; while(scanf("%d",&n)&&n){ int a[55],sum=0; for(i=0;i scanf("%d",&a[i]); sum+=a[i]; } al=sum/n原创 2012-11-29 20:42:38 · 497 阅读 · 0 评论 -
poj1247
#include int main(){ int a[31]; int n,tmp,tol; while(1){ int sum=0; scanf("%d",&n); if(n==0)break; for(int i=1;i scanf("%d",&a[i]); sum+=a[i];} if((sum%2!=0)){pr原创 2012-11-19 19:15:10 · 436 阅读 · 0 评论 -
poj1887
#include #define max 32769//32767 int main (){ int n=1; while (1){ int d_max=1; int num=0,max_s=1; int a[max];//存储数组 int b[max];//记录最长 scanf("%原创 2012-11-20 20:19:36 · 508 阅读 · 0 评论 -
poj1463
1原创 2012-11-23 20:27:05 · 507 阅读 · 0 评论 -
poj2390
Description Farmer John made a profit last year! He would like to invest it well but wonders how much money he will make. He knows the interest rate R (an integer between 0 and 20) that is compound原创 2012-12-11 20:28:23 · 557 阅读 · 0 评论 -
poj3278Catch That Cow 经典宽搜讲解
3278 Catch That Cow Description Farmer Johnhas been informed of the location of a fugitive cow and wants to catch herimmediately. He starts at a pointN (0 ≤ N ≤ 100,000) on a numberline and the cow原创 2013-04-19 14:31:57 · 805 阅读 · 0 评论
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