题目链接:https://nanti.jisuanke.com/t/T1372
算法特工队QQ群:979618872 (伸手党绕边,欢迎有良好基础的人加入)
//
// Created by Leo Lee on 2019/4/6.
//
#include <iostream>
using namespace std;
int main(){
int n;
cin>>n;
int sign = 0;
for(int i = 0;i<=n/5;i++){
for(int j = 0;j<=n/3;j++){
for(int k = 0;k<=n*3;k+=3){
if(i+j+k==n && i*5+j*3+k/3 == n){
printf("%d %d %d\n",i,j,k);
sign = 1;
}
}
}
}
if(sign==0)
cout<<"No Answer."<<endl;
return 0;
}