CPP2022-06-分支结构

原创已于 2022-10-12 23:23:08 修改 · 454 阅读

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#c++ #开发语言

于 2022-10-12 15:25:50 首次发布

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本文包含了一系列编程练习题的答案解析，包括判断题、选择题、函数题及编程题等，涉及条件判断、函数定义、算术运算等内容，适用于初学者进行实践操作。

一.判断题

TTTFF,TFTFT,

二.单选题

DCCDB,DADBB

三.函数题

int intMax(int x, int y)
{
    if(x>y)
    {
        return x;
    }
    else 
    {
        return y;
    }
}

(y%4==0&&y%100!=0)||y%400==0

n%10==7

int sign(const float x)
{
    if(x>0)
    {
        return 1;
    }
    else if(x==0)
    {
        return 0;
    }
    else
    {
        return -1;
    }
}

char ToRank(double score)
{
    if(score>=90&&score<=100)
    {
        return 'A';
    }
    else if(score>=80&&score<90)
    {
        return 'B';
    }
    else if(score>=70&&score<=80)
    {
        return 'C';
    }
    else if(score>=60&&score<70)
    {
        return 'D';
    }
    else
    {
        return 'E';
    }
}

char ToRank(double score)
{
	int a;
    a=score/10;
    switch(a)
    {
            case 10: return'A'; break;
            case 9: return'A'; break;
            case 8: return'B'; break;
            case 7: return'C'; break;
            case 6: return'D'; break;
            default: return'E'; break;
    }
}

四.编程题

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b,d;
    char c;
    cin>>a>>c>>b;
    if(c=='+')
    {
        d=a+b;
        cout<<d<<endl;
    }
    else if(c=='-')
    {
        d=a-b;
        cout<<d<<endl;
    }
    else if(c=='*')
    {
        d=a*b;
        cout<<d<<endl;
    }
    else if(c=='/')
    {
        d=a/b;
        cout<<d<<endl;
    }
    else if(c=='%')
    {
        d=a%b;
        cout<<d<<endl;
    }
    else
    {
        cout<<"ERROR"<<endl;
    }
    return 0;
}

c语言用法

#include<stdio.h>
int main(){
    int n;
    int count=0;
    printf("[1] apple\n[2] pear\n[3] orange\n[4] grape\n[0] exit\n");
    while (count<5){
        scanf("%d",&n);
        count++;
        if (n==0)
        return 0;
        if (n>0&&n<5){
            switch(n){
                case 1:printf("price = 3.00\n");break;
                case 2:printf("price = 2.50\n");break;
                case 3:printf("price = 4.10\n");break;
                case 4:printf("price = 10.20\n");break;
            }
        }
        else
        printf("price = 0.00\n");
    }
    return 0;
}

c++用法

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    int count=0;
    cout<<"[1] apple"<<endl;
    cout<<"[2] pear"<<endl;
    cout<<"[3] orange"<<endl;
    cout<<"[4] grape"<<endl;
    cout<<"[0] exit"<<endl;
    while(count<5)
    {
        cin>>n;
        count=count+1;
        if(n==0) return 0;
        else if(n>0&&n<=5)
        {
            switch(n)
            {
                case 1 : cout<<"price = 3.00"<<endl; break;
                case 2 : cout<<"price = 2.50"<<endl; break;
                case 3 : cout<<"price = 4.10"<<endl; break;
                case 4 : cout<<"price = 10.20"<<endl; break;
            }
        }
        else
        {
            cout<<"price = 0.00"<<endl;
        }
    }
    return 0;
}