hdu 6043 KazaQ's Socks

Problem Description

KazaQ wears socks everyday.

At the beginning, he has n pairs of socks numbered from 1 to n in his closets. 

Every morning, he puts on a pair of socks which has the smallest number in the closets. 

Every evening, he puts this pair of socks in the basket. If there are n−1 pairs of socks in the basket now, lazy KazaQ has to wash them. These socks will be put in the closets again in tomorrow evening.

KazaQ would like to know which pair of socks he should wear on the k-th day.

 

Input

The input consists of multiple test cases. (about 2000)

For each case, there is a line contains two numbers n,k (2≤n≤109,1≤k≤1018).

 

Output

For each test case, output "Case #x: y" in one line (without quotes), where x indicates the case number starting from 1 and y denotes the answer of corresponding case.

 

Sample Input

3 7
3 6
4 9

 

Sample Output

Case #1: 3
Case #2: 1
Case #3: 2
写几组数就会发现简单的规律，例如5的时候就是 1 2 3 4 5 1 2 3 4 1 2 3 5 1 2 3 4 1 2 3 5,
ac代码：
#include <iostream>
#include <cstdio>
#include <cstring>
#include <stdio.h>
#include <stdlib.h>
#include <algorithm>
#include <math.h>
using namespace std;

int main()
{
    long long n,k;
    int cot=1;
    while(scanf("%lld%lld",&n,&k)!=EOF)
    {
        printf("Case #%d: ",cot++);
        if(k<=n)
            printf("%lld\n",k);
        else
        {
            k=k-n;
            long long flag=k/(n-1);
            if(flag%2==1)
            {
                if(k%(n-1)!=0)
                    printf("%lld\n",k%(n-1));
                else
                    printf("%lld\n",n-1);
            }
            else
            {
                if(k%(n-1)!=0)
                    printf("%lld\n",k%(n-1));
                else
                    printf("%lld\n",n);
            }
        }
    }
    return 0;
}