两个数组的交集，并集，差集。

#include <iostream>
#include<string>
using namespace  std;
int main()
{
int a[] = { 1, 2, 4, 5, 7, 6 };
int b[] = { 1, 4, 5, 6, 9 };
int num11 = sizeof(a) / sizeof(a[0]);
int num2 = sizeof(b) / sizeof(b[0]);
bool suc = false;
int num1 = num11;
for (int i = 0; i < num1; )
{
suc = false;
for (int j = i; j < num2; j++)
{
if (a[i] == b[j])
{
int temp = b[i];
b[i] = b[j];
b[j] = temp;
suc = true;
break;
}
}
if (!suc)
{
int temp = a[i];
a[i] = a[--num1];
a[num1] = temp;
}
else
i++;//读者注意：若没有进行if(a[i]==b[j])这一步的话，i的值是不加1的。。。。。

}
//输出交集；
cout << "交" << endl;
for (int i = 0; i < num1; i++)
{


cout << a[i] << " ";
}
cout << endl;
//输出并集；
cout << "并" << endl;
for (int i = 0; i < num1; i++)
{
cout << a[i] << " ";
}
for (int i = num1; i < num11; i++)
{
cout << a[i] << " ";
}
for (int j = num1; j < num2; j++)
{
cout << b[j] << " ";
}
cout << endl;
//输出差积：
cout << "差" << endl;
cout << "only in a" << endl;
for (int i =num1; i < num11; i++)
{
cout << a[i] << " ";
}
cout << endl;
cout << "only in b" << endl;
for (int i = num1; i < num2; i++)
{
cout <<b[i] << " ";
}
cout << endl;
return 0;
}