如何在动态生成的GridView中动态生成超链接并实现其功能

最新推荐文章于 2021-05-12 07:49:19 发布

流萤~飞火

最新推荐文章于 2021-05-12 07:49:19 发布

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文章标签： c# asp.net

本文链接：https://blog.youkuaiyun.com/the_sky_of_star/article/details/115611523

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    protected void gvEmployee_RowDataBound(object sender, GridViewRowEventArgs e)
    {
        GridViewManager.SetRowBackColor(e.Row);
        GridViewManager.SetRowBackColor(gvEmployee.Rows);
        var a = dt.Rows[0]["EnglishName"].ToString();
         
        if (e.Row.RowType == DataControlRowType.DataRow)
        {

            TableCellCollection cells = e.Row.Cells;

            string led_id = e.Row.Cells[0].Text;
            HyperLink linkField = new HyperLink();
            linkField.Text = led_id;
            e.Row.Cells[0].Controls.Add(linkField);
            linkField.Attributes.Add("onclick", "window.open('../UISysAdmin/UserView.aspx?UserId="
              + led_id + "','','width=1000,height=600,left=300,top=100,scrollbars=yes,resizable:0,status:0,directories:0,toolbar:0,location:0,,menubar:0')");
            linkField.Attributes.Add("onmouseover", "this.style.cursor='hand'");

        }
    }