237. Delete Node in a Linked List

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本文介绍了一种在单链表中删除指定节点（除尾节点外）的方法，仅通过访问该节点实现。通过修改节点值及指向下一个节点的指针完成删除操作，并提供了完整的Python代码示例，运行效率高。

237. Delete Node in a Linked List

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Discription:

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

Analyze:

Code 1:

    # Definition for singly-linked list.
    # class ListNode(object):
    #     def __init__(self, x):
    #         self.val = x
    #         self.next = None

    class Solution(object):
        def show(self,node):
            while(node):
                print node.val
                node=node.next
        def deleteNode(self, node):
            """
            :type node: ListNode
            :rtype: void Do not return anything, modify node in-place instead.
            """
            if node and node.next:
                node.val=node.next.val    ##Modifying formal parameter dose not work
                node.next=node.next.next  ##the true way is to modify the actual parameter in internal storage