如何用c语言检测密码在60秒内输入的次数，要是次数超过5次，则返回true(1)?-优快云博客

下面是gpt给出的回答，不知道是否正确，请看代码：


#include <stdio.h>
#include <stdlib.h>
#include <time.h>
typedef unsigned char   uint8_t;
typedef unsigned  int   uint32_t;
#define MAX_ERRORS 5  //timer errors
#define TIME_LIMIT 60 // in seconds

// Function to check if the timestamp is within the 1-minute window
int is_within_time_limit(time_t start_time, time_t current_time) {
    return (difftime(current_time, start_time) <= TIME_LIMIT);
}

//timestamps : time ; error_event : error:1 
uint8_t monitor_errors(uint32_t timestamps,uint8_t error_event){
    static uint8_t  error_count = 0;
    static uint32_t monitor_start_time = 0;
    static uint8_t  alarm_triggered = 0;

    if (monitor_start_time == 0 || !error_event) {
        monitor_start_time = timestamps;
        error_count = 0;
        alarm_triggered = 0;
        printf("\nMonitoring restarted. Timestamp: %ld\n", monitor_start_time);
    }

    // Check if the current event is within the 1-minute monitoring window
    if (is_within_time_limit(monitor_start_time, timestamps)) {
        if (error_event) {
            error_count++;
            printf("Error detected. Current error count: %d\n", error_count);
        }

        if (error_count >= MAX_ERRORS && !alarm_triggered) {
            alarm_triggered = 1;
            printf("ALARM! Too many errors detected within 1 minute.\n");
        }
    } else {
        // Outside the 1-minute window, reset monitoring
        monitor_start_time = timestamps;
        error_count = error_event ? 1 : 0;
        alarm_triggered = 0;
        printf("Monitoring window reset. Timestamp: %ld\n", monitor_start_time);
    }
    return alarm_triggered;
}

int main() {
    // Simulated series of events with timestamps and error flags
    uint32_t start = 1000;
    uint8_t  step   = 20;
    time_t  timestamps[] = {start, start+step*2, start+step*3, start+step*4, start+step*5, start+step*6, start+step*7, start+step*8, start+step*9, start+step*10};
    int     error_events[]  = {1, 1, 1, 1, 1, 1, 0, 1, 0, 1};
    int     num_events = sizeof(error_events) / sizeof(error_events[0]);

    for (int i = 0; i < num_events; i++) {
        int alarm = monitor_errors(timestamps[i], error_events[i]);
        if (alarm) {
            printf("Action required due to alarm state.\n");
        }
    }

    return 0;
}

main 函数开始执行，首先手动创建2个数组，代表用户在输入秘密时的时间参数以及错误密码标志，密码错误即时1,密码正确0，(当密码正确时0 重新统计)。

不知道这个函数对不对~~~