pat 1083 List Grades

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本文介绍了一种算法，该算法能够读取一系列学生记录（包括姓名、ID和成绩），并根据给定的成绩区间筛选和排序这些记录。最终输出成绩位于指定区间内学生的姓名和ID，并按成绩降序排列。

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <vector>
#include <algorithm>
using namespace std;

int N;

struct Record
{
	char name[12];
	char ID[12];
	int scores;
};
vector<Record> vec;

bool cmpGrade (const Record &stue1, const Record &stu2) {
	return stu2.scores < stue1.scores;
}

int print(int istart, int iend) {
	int cnt = 0;
	for (int i = 0; i < N; ++i)
	{
		if(vec[i].scores >= istart && vec[i].scores <= iend) {
			cnt++;
			printf("%s %s\n", vec[i].name, vec[i].ID);
		}
	}
	return cnt;
}

int main() {
	cin >> N;

	Record record;
	char name[12], ID[12];
	int scores, istart, iend;

	for (int i = 0; i < N; ++i)
	{
		scanf("%s %s %d", name, ID, &scores);
		strcpy(record.name, name);
		strcpy(record.ID, ID);
		record.scores = scores;
		vec.push_back(record);
	}

	scanf("%d %d", &istart, &iend);
	sort(vec.begin(), vec.end(), cmpGrade);
	int ans = print(istart, iend);
	if(ans == 0) printf("NONE\n");
	return 0;
}