Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are mand n respectively.
因为A总是足够大,所以最后的结果有n+m个element,那么merge其实就是比较大小,从后往前merge就不会有挪动位置的复杂度, 其中要注意的一个corner case就是A的index没了。。。。
class Solution {
public:
void merge(int A[], int m, int B[], int n) {
int i=m-1;
int j=n-1;
int k=m+n-1;
while(j>=0){
A[k--]=i<0||A[i]<B[j]? B[j--]:A[i--];
}
}
};