[LeetCode]27. Remove Element【&26. Remove Duplicates from Sorted Array】

本文介绍两种基本数组操作:去除指定元素及删除排序数组中的重复项。通过实例演示如何使用原地算法,不借助额外空间实现这些功能。

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27 . Remove Element
Easy

Given an array and a value, remove all instances of that value in place and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

Example:
Given input array nums = [3,2,2,3], val = 3

Your function should return length = 2, with the first two elements of nums being 2.

0ms:

public int removeElement(int[] nums, int val) {
        int p = 0;
        for(int i=0;i<nums.length;i++){
            while(i<nums.length&&nums[i]==val)
                i++;

            if(i==nums.length)
                break;
            nums[p]=nums[i];
            p++;
        }
        return p;
    }

26 . Remove Duplicates from Sorted Array
Easy

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn’t matter what you leave beyond the new length.

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