Authid Current_User的使用

本文介绍Oracle数据库中如何使存储过程能够利用用户的Role权限来执行操作。通过对比展示,在未使用Authid Current_User声明前存储过程无法直接利用Role权限,而加入此声明后则可以正常使用。这一技巧可以有效简化复杂的权限配置。

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我们知道,用户拥有的role权限在存储过程是不可用的。遇到这种情况,我们一般需要显式进行系统权限,如grant create table to suk;但这种方法太麻烦,有时候可能需要进行非常多的授权才能执行存储过程,实际上,oracle给我们提供了在存储过程中使用role权限的方法:修改存储过程,加入Authid Current_User时存储过程可以使用role权限。

  我们知道,用户拥有的role权限在存储过程是不可用的。如:

    SQL> select * from dba_role_privs where grantee='SUK';

    GRANTEE GRANTED_ROLE ADMIN_OPTION DEFAULT_ROLE
    ------------ ------------ ------------ ------------
    SUK DBA NO YES
    SUK CONNECT NO YES
    SUK RESOURCE NO YES

  用户SUK拥有DBA这个role

  再创建一个测试存储过程:

    create or replace procedure p_create_table
    is
    begin
    Execute Immediate 'create table create_table(id int)';
    end p_create_table;

  然后测试

    SQL> exec p_create_table;

    begin p_create_table; end;

    ORA-01031: 权限不足
    ORA-06512: 在"SUK.P_CREATE_TABLE", line 3
    ORA-06512: 在line 1

  可以看到,即使拥有DBA role,也不能创建表。role在存储过程中不可用。

  遇到这种情况,我们一般需要显式进行系统权限,如grant create table to suk;

  但这种方法太麻烦,有时候可能需要进行非常多的授权才能执行存储过程

  实际上,oracle给我们提供了在存储过程中使用role权限的方法:

  修改存储过程,加入Authid Current_User时存储过程可以使用role权限。

    create or replace procedure p_create_table
    Authid Current_User is
    begin
    Execute Immediate 'create table create_table(id int)';
    end p_create_table;

  再尝试执行:

    SQL> exec p_create_table;

    PL/SQL procedure successfully completed

  已经可以执行了。

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### Cause: java.sql.SQLSyntaxErrorException: ORA-01790: 式には対応する式と同じデータ型を持つ必要があります ; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: ORA-01790: 式には対応する式と同じデータ型を持つ必要があります ] with root cause Error : 1790, Position : 213, Sql = MERGE INTO A01_PROJECT_MEMBER t USING ( SELECT :1 AS PROJECT_ID, :2 AS EMPLOYEE_ID, :3 AS EMPLOYEE_NAME, :4 AS ROLE, :5 AS START_DATE, :6 AS END_DATE, 0 AS DEL_FLG, :7 AS INSERT_USER_ID, :8 AS UPDATE_USER_ID FROM dual UNION ALL SELECT :9 AS PROJECT_ID, :10 AS EMPLOYEE_ID, :11 AS EMPLOYEE_NAME, :12 AS ROLE, :13 AS START_DATE, :14 AS END_DATE, 0 AS DEL_FLG, :15 AS INSERT_USER_ID, :16 AS UPDATE_USER_ID FROM dual ) s ON ( t.PROJECT_ID = s.PROJECT_ID AND t.EMPLOYEE_ID = s.EMPLOYEE_ID AND t.START_DATE = s.START_DATE ) WHEN MATCHED THEN UPDATE SET t.EMPLOYEE_NAME = s.EMPLOYEE_NAME, t.ROLE = s.ROLE, t.END_DATE = CURRENT_TIMESTAMP, t.DEL_FLG = s.DEL_FLG, t.INSERT_USER_ID = s.INSERT_USER_ID, t.INSERT_TIME = t.INSERT_TIME, t.UPDATE_USER_ID = s.UPDATE_USER_ID, t.UPDATE_TIME = CURRENT_TIMESTAMP WHEN NOT MATCHED THEN INSERT ( PROJECT_ID, EMPLOYEE_ID, EMPLOYEE_NAME, ROLE, START_DATE, END_DATE, DEL_FLG, INSERT_USER_ID, INSERT_TIME, UPDATE_USER_ID, UPDATE_TIME ) VALUES ( s.PROJECT_ID, s.EMPLOYEE_ID, s.EMPLOYEE_NAME, s.ROLE,    CURRENT_TIMESTAMP, null, s.DEL_FLG, s.INSERT_USER_ID, CURRENT_TIMESTAMP, s.UPDATE_USER_ID, CURRENT_TIMESTAMP ), OriginalSql = MERGE INTO A01_PROJECT_MEMBER t USING ( SELECT ? AS PROJECT_ID, ? AS EMPLOYEE_ID, ? AS EMPLOYEE_NAME, ? AS ROLE, ? AS START_DATE, ? AS END_DATE, 0 AS DEL_FLG, ? AS INSERT_USER_ID, ? AS UPDATE_USER_ID FROM dual UNION ALL SELECT ? AS PROJECT_ID, ? AS EMPLOYEE_ID, ? AS EMPLOYEE_NAME, ? AS ROLE, ? AS START_DATE, ? AS END_DATE, 0 AS DEL_FLG, ? AS INSERT_USER_ID, ? AS UPDATE_USER_ID FROM dual ) s ON ( t.PROJECT_ID = s.PROJECT_ID AND t.EMPLOYEE_ID = s.EMPLOYEE_ID AND t.START_DATE = s.START_DATE ) WHEN MATCHED THEN UPDATE SET t.EMPLOYEE_NAME = s.EMPLOYEE_NAME, t.ROLE = s.ROLE, t.END_DATE = CURRENT_TIMESTAMP, t.DEL_FLG = s.DEL_FLG, t.INSERT_USER_ID = s.INSERT_USER_ID, t.INSERT_TIME = t.INSERT_TIME, t.UPDATE_USER_ID = s.UPDATE_USER_ID, t.UPDATE_TIME = CURRENT_TIMESTAMP WHEN NOT MATCHED THEN INSERT ( PROJECT_ID, EMPLOYEE_ID, EMPLOYEE_NAME, ROLE, START_DATE, END_DATE, DEL_FLG, INSERT_USER_ID, INSERT_TIME, UPDATE_USER_ID, UPDATE_TIME ) VALUES ( s.PROJECT_ID, s.EMPLOYEE_ID, s.EMPLOYEE_NAME, s.ROLE,    CURRENT_TIMESTAMP, null, s.DEL_FLG, s.INSERT_USER_ID, CURRENT_TIMESTAMP, s.UPDATE_USER_ID, CURRENT_TIMESTAMP ), Error Msg = ORA-01790: 式には対応する式と同じデータ型を持つ必要があります 哪个地方报错了
最新发布
07-25
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