oracle authid current_user详解

本文介绍了在Oracle PL/SQL环境中如何正确处理存储过程中的权限问题,特别是如何利用AUTHID CURRENT_USER来实现角色权限的使用,避免繁琐的显式授权。

在编写PLSQL程序时,对于授权的考虑很重要。ORACLE PLSQL中提供两种授权选择:

--AUTHID DEFINER (定义者权限):指编译存储对象的所有者。也是默认权限模式。

--AUTHID CURRENT_USER(调用者权限):指拥有当前会话权限的模式,这可能和当前登录用户相同或不同(alter session set current_schema 可以改变调用者Schema)

 

Oracle存储过程中创建表的权限

SQL> exec p_create_table;
ORA-01031: 权限不足

即使拥有DBA role,也不能创建表。role在存储过程中不可用。
遇到这种情况,我们一般需要显式进行系统权限,如grant create table to eu_user;
但这种方法太麻烦,有时候可能需要进行非常多的授权才能执行存储过程
实际上,oracle给我们提供了在存储过程中使用role权限的方法:
修改存储过程,加入Authid Current_User时存储过程可以使用role权限。
create or replace procedure p_create_table
Authid Current_User is
begin
Execute Immediate 'create table crm_newtable(id number)';
end p_create_table;
再尝试执行:
SQL> exec p_create_table;
PL/SQL procedure successfully completed

### Cause: java.sql.SQLSyntaxErrorException: ORA-01790: 式には対応する式と同じデータ型を持つ必要があります ; bad SQL grammar []; nested exception is java.sql.SQLSyntaxErrorException: ORA-01790: 式には対応する式と同じデータ型を持つ必要があります ] with root cause Error : 1790, Position : 213, Sql = MERGE INTO A01_PROJECT_MEMBER t USING ( SELECT :1 AS PROJECT_ID, :2 AS EMPLOYEE_ID, :3 AS EMPLOYEE_NAME, :4 AS ROLE, :5 AS START_DATE, :6 AS END_DATE, 0 AS DEL_FLG, :7 AS INSERT_USER_ID, :8 AS UPDATE_USER_ID FROM dual UNION ALL SELECT :9 AS PROJECT_ID, :10 AS EMPLOYEE_ID, :11 AS EMPLOYEE_NAME, :12 AS ROLE, :13 AS START_DATE, :14 AS END_DATE, 0 AS DEL_FLG, :15 AS INSERT_USER_ID, :16 AS UPDATE_USER_ID FROM dual ) s ON ( t.PROJECT_ID = s.PROJECT_ID AND t.EMPLOYEE_ID = s.EMPLOYEE_ID AND t.START_DATE = s.START_DATE ) WHEN MATCHED THEN UPDATE SET t.EMPLOYEE_NAME = s.EMPLOYEE_NAME, t.ROLE = s.ROLE, t.END_DATE = CURRENT_TIMESTAMP, t.DEL_FLG = s.DEL_FLG, t.INSERT_USER_ID = s.INSERT_USER_ID, t.INSERT_TIME = t.INSERT_TIME, t.UPDATE_USER_ID = s.UPDATE_USER_ID, t.UPDATE_TIME = CURRENT_TIMESTAMP WHEN NOT MATCHED THEN INSERT ( PROJECT_ID, EMPLOYEE_ID, EMPLOYEE_NAME, ROLE, START_DATE, END_DATE, DEL_FLG, INSERT_USER_ID, INSERT_TIME, UPDATE_USER_ID, UPDATE_TIME ) VALUES ( s.PROJECT_ID, s.EMPLOYEE_ID, s.EMPLOYEE_NAME, s.ROLE,    CURRENT_TIMESTAMP, null, s.DEL_FLG, s.INSERT_USER_ID, CURRENT_TIMESTAMP, s.UPDATE_USER_ID, CURRENT_TIMESTAMP ), OriginalSql = MERGE INTO A01_PROJECT_MEMBER t USING ( SELECT ? AS PROJECT_ID, ? AS EMPLOYEE_ID, ? AS EMPLOYEE_NAME, ? AS ROLE, ? AS START_DATE, ? AS END_DATE, 0 AS DEL_FLG, ? AS INSERT_USER_ID, ? AS UPDATE_USER_ID FROM dual UNION ALL SELECT ? AS PROJECT_ID, ? AS EMPLOYEE_ID, ? AS EMPLOYEE_NAME, ? AS ROLE, ? AS START_DATE, ? AS END_DATE, 0 AS DEL_FLG, ? AS INSERT_USER_ID, ? AS UPDATE_USER_ID FROM dual ) s ON ( t.PROJECT_ID = s.PROJECT_ID AND t.EMPLOYEE_ID = s.EMPLOYEE_ID AND t.START_DATE = s.START_DATE ) WHEN MATCHED THEN UPDATE SET t.EMPLOYEE_NAME = s.EMPLOYEE_NAME, t.ROLE = s.ROLE, t.END_DATE = CURRENT_TIMESTAMP, t.DEL_FLG = s.DEL_FLG, t.INSERT_USER_ID = s.INSERT_USER_ID, t.INSERT_TIME = t.INSERT_TIME, t.UPDATE_USER_ID = s.UPDATE_USER_ID, t.UPDATE_TIME = CURRENT_TIMESTAMP WHEN NOT MATCHED THEN INSERT ( PROJECT_ID, EMPLOYEE_ID, EMPLOYEE_NAME, ROLE, START_DATE, END_DATE, DEL_FLG, INSERT_USER_ID, INSERT_TIME, UPDATE_USER_ID, UPDATE_TIME ) VALUES ( s.PROJECT_ID, s.EMPLOYEE_ID, s.EMPLOYEE_NAME, s.ROLE,    CURRENT_TIMESTAMP, null, s.DEL_FLG, s.INSERT_USER_ID, CURRENT_TIMESTAMP, s.UPDATE_USER_ID, CURRENT_TIMESTAMP ), Error Msg = ORA-01790: 式には対応する式と同じデータ型を持つ必要があります 哪个地方报错了
最新发布
07-25
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