1116. Come on! Let's C (20)
"Let's C" is a popular and fun programming contest hosted by the College of Computer Science and Technology, Zhejiang University. Since the idea of the contest is for fun, the award rules are funny as the following:
0. The Champion will receive a "Mystery Award" (such as a BIG collection of students' research papers...).
1. Those who ranked as a prime number will receive the best award -- the Minions (小黄人)!
2. Everyone else will receive chocolates.
Given the final ranklist and a sequence of contestant ID's, you are supposed to tell the corresponding awards.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (<=10000), the total number of contestants. Then N lines of the ranklist follow, each in order gives a contestant's ID (a 4-digit number). After the ranklist, there is a positive integer K followed by K query ID's.
Output Specification:
For each query, print in a line "ID: award" where the award is "Mystery Award", or "Minion", or "Chocolate". If the ID is not in the ranklist, print "Are you kidding?" instead. If the ID has been checked before, print "ID: Checked".
Sample Input:6 1111 6666 8888 1234 5555 0001 6 8888 0001 1111 2222 8888 2222Sample Output:
8888: Minion 0001: Chocolate 1111: Mystery Award 2222: Are you kidding? 8888: Checked 2222: Are you kidding?
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cstring>
using namespace std;
typedef long long int ll;
struct Node{
int res;
int flag;
Node(){
res = flag = 0;
}
};
Node Rank[10005];
int prime[10005];
void Prime(){
for(int i=0; i<=10000; i++)
prime[i] = 1;
prime[0] = prime[1] = 0;
for(int i=2; i<=10000; i++){
if(prime[i]){
for(int j=2*i; j<=10000; j+=i)
prime[j] = 0;
}
}
}
int main(){
Prime();
int count = 0;
int N;
scanf("%d",&N);
int ID;
for(int i=1; i<=N; i++){
scanf("%d",&ID);
Rank[ID].res = ++count;
}
int K;
scanf("%d",&K);
for(int i=1; i<=K; i++){
scanf("%d",&ID);
if(Rank[ID].res==0)
printf("%04d: Are you kidding?\n",ID);
else if(prime[Rank[ID].res]){
if(Rank[ID].flag == 0){
printf("%04d: Minion\n",ID);
Rank[ID].flag = 1;
}
else
printf("%04d: Checked\n",ID);
}
else if(Rank[ID].res==1){
if(Rank[ID].flag==0){
printf("%04d: Mystery Award\n",ID);
Rank[ID].flag = 1;
}
else
printf("%04d: Checked\n",ID);
}
else{
if(Rank[ID].flag==0){
printf("%04d: Chocolate\n",ID);
Rank[ID].flag = 1;
}
else
printf("%04d: Checked\n",ID);
}
}
return 0;
}
编程竞赛奖品分配
本文介绍了一个有趣的编程竞赛“Let's C”的奖品分配规则,并提供了一段C++代码实现,该程序根据参赛者的最终排名为其分配不同的奖品。
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