计算输入日期的下一天的nextDate()

最新推荐文章于 2023-04-07 16:15:39 发布

spf19871001

最新推荐文章于 2023-04-07 16:15:39 发布

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分类专栏： ASP.NET 文章标签：软件测试作业测试

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本文介绍了一个用于计算指定日期之后的下一个日期的算法实现。该算法通过输入当前的年、月、日，可以返回下一天的具体日期，并考虑了闰年和平年的不同情况。

同样是软件测试课程的作业，测试过程不解释，贴图贴代码。

public static ArrayList NextDate(int nowYear, int nowMonth, int nowDay) { ArrayList arr = new ArrayList(); if (nowYear <= 3000 && nowYear >= 1000 && nowMonth <= 12 && nowMonth >= 1 && nowDay >= 1 && nowDay <= getDays(nowYear, nowMonth)) { int nextYear; int nextMonth; int nextDay; if (nowDay == getDays(nowYear, nowMonth)) { if (nowMonth == 12) { nextYear = nowYear + 1; nextMonth = 1; nextDay = 1; } else { nextYear = nowYear; nextMonth = nowMonth + 1; nextDay = 1; } } else { nextYear = nowYear; nextMonth = nowMonth; nextDay = nowDay + 1; } arr.Add(nextYear); arr.Add(nextMonth); arr.Add(nextDay); } else { arr.Add("错误年份"); arr.Add("错误月份"); arr.Add("错误天数"); } return arr; } protected static bool isRun(int year) { if (year % 4 == 0 && year % 400 != 0) { return true; } return false; } protected static int getDays(int year, int month) { int days = 0; switch (month) { case 1: case 3: case 5: case 7: case 8: case 10: case 12: days = 31; break; case 2: days = isRun(year) ? 29 : 28; break; case 4: case 6: case 9: case 11: days = 30; break; } return days; }