Re 正则提取字符串中所有的链接

提取规则如下

根据URL的规则，设计一段正则表达式，提取出一段文本中的所有网址

Python

import <span class="wp_keywordlink_affiliate"><a href="https://www.168seo.cn/tag/re" title="View all posts in re" target="_blank">re</a></span> <span class="wp_keywordlink_affiliate"><a href="https://www.168seo.cn/tag/re" title="View all posts in re" target="_blank">re</a></span>.findall('(https?://[a-zA-Z0-9\.\?/%-_]*)',r.text)

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import re re . findall ( '(https?://[a-zA-Z0-9\.\?/%-_]*)' , r . text )

测试：

Python

In [13]: import re,<span class="wp_keywordlink_affiliate"><a href="https://www.168seo.cn/tag/requests" title="View all posts in requests" target="_blank">requests</a></span> In [14]: url = "https://www.168seo.cn" In [15]: r = <span class="wp_keywordlink_affiliate"><a href="https://www.168seo.cn/tag/requests" title="View all posts in requests" target="_blank">requests</a></span>.get(url) In [16]: r Out[16]: <Response [200]> In [17]: re.findall('(https?://[a-zA-Z0-9\.\?/%-_]*)',r.text)

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In [ 13 ] : import re , requests   In [ 14 ] : url = "https://www.168seo.cn"   In [ 15 ] : r = requests . get ( url )   In [ 16 ] : r Out [ 16 ] : < Response [ 200 ] >   In [ 17 ] : re . findall ( '(https?://[a-zA-Z0-9\.\?/%-_]*)' , r . text )

输出如下：

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