133. Clone Graph
Medium
Given the head of a graph, return a deep copy (clone) of the graph. Each node in the graph contains a label
(int
) and a list (List[UndirectedGraphNode]
) of its neighbors
. There is an edge between the given node and each of the nodes in its neighbors.
OJ's undirected graph serialization (so you can understand error output):
Nodes are labeled uniquely.
We use #
as a separator for each node, and ,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph {0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by #
.
- First node is labeled as
0
. Connect node0
to both nodes1
and2
. - Second node is labeled as
1
. Connect node1
to node2
. - Third node is labeled as
2
. Connect node2
to node2
(itself), thus forming a self-cycle.
Visually, the graph looks like the following:
1 / \ / \ 0 --- 2 / \ \_/
Note: The information about the tree serialization is only meant so that you can understand error output if you get a wrong answer. You don't need to understand the serialization to solve the problem.
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (null == node) {
return null;
}
Queue<UndirectedGraphNode> queue = new ArrayDeque<>();
queue.add(node);
Map<Integer, UndirectedGraphNode> nodes = new HashMap<>();
Map<Integer, UndirectedGraphNode> copyNodes = new HashMap<>();
while (!queue.isEmpty()) {
UndirectedGraphNode tNode = queue.poll();
nodes.put(tNode.label, tNode);
copyNodes.put(tNode.label, new UndirectedGraphNode(tNode.label));
for (UndirectedGraphNode n: tNode.neighbors) {
if (!nodes.containsKey(n.label)) {
queue.add(n);
}
}
}
for (Map.Entry<Integer, UndirectedGraphNode> entry: nodes.entrySet()) {
for (UndirectedGraphNode n : entry.getValue().neighbors) {
copyNodes.get(entry.getKey()).neighbors.add(copyNodes.get(n.label));
}
}
return copyNodes.get(node.label);
}
}