184. Department Highest Salary

最新推荐文章于 2020-10-08 00:29:30 发布

SnailRunFast

最新推荐文章于 2020-10-08 00:29:30 发布

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分类专栏： Leet Code SQL 文章标签： Department Highest S

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本文介绍了一个SQL查询案例，旨在找出每个部门中薪资最高的员工。通过使用子查询和连接操作，可以有效地从Employee和Department两个表中获取所需信息。

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The Employee table holds all employees. Every employee has an Id, a salary, and there is also a column for the department Id.

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
+----+-------+--------+--------------+

The Department table holds all departments of the company.

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

Write a SQL query to find employees who have the highest salary in each of the departments. For the above tables, Max has the highest salary in the IT department and Henry has the highest salary in the Sales department.

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| Sales      | Henry    | 80000  |
+------------+----------+--------+

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MySQL:

# Write your MySQL query statement below

select 
    dd.Department   as Department,
    ee.Name         as Employee,
    dd.Salary       as Salary
from
    Employee ee,
    (
    select 
        max(e.DepartmentId)     as DepartmentId,
        d.Name                  as Department,
        max(e.Salary)           as Salary
    from
        Employee e,
        Department d
    where
        e.DepartmentId = d.Id
    group by
        d.Name
    ) dd
where
    ee.Salary = dd.Salary
    and ee.DepartmentId = dd.DepartmentId
;