Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ]
Solution:
Tips:
sort array first, fix one number in either of the end, then from two sides to middle.
Java Code:
public class Solution {
public List<List<Integer>> threeSum(int[] nums) {
Arrays.sort(nums);
List<List<Integer>> result = new ArrayList<>();
for (int i = nums.length - 1; i >= 2; i--) {
int left = 0;
int right = i - 1;
while (left < right) {
int sum = -(nums[left] + nums[right]);
if (sum == nums[i]) {
result.add(Arrays.asList(nums[left], nums[right], nums[i]));
while (++left < right && nums[left - 1] == nums[left]);
while (--right > left && nums[right] == nums[right + 1]);
} else if (sum > nums[i]) {
left++;
} else {
right--;
}
}
while (i >= 2 && nums[i] == nums[i - 1]) {
i--;
}
}
return result;
}
}