ACM 水题

Problem Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

+A -A
+1A 12
1A -9
-1A -12
1A -AA

 

Sample Output

0
2C
11
-2C
-90

思路：用十六进制输入然后进行加减 设a,b,c中将其定义为_int 64 且%I64X不能输出负数输出时应该进行处理。

代码：

#include <stdio.h>

int main(){
    __int64 a;
    __int64 b;
    __int64 c;
    while(scanf("%I64X%I64X",&a,&b)!=EOF)

       {
        c=a+b;
        if(c<0){
            c=-c;
            printf("-");
        }
        printf("%I64X\n",c);
    }
    return 0;
}