ACM 第一天水题（2）

最新推荐文章于 2021-04-21 13:21:58 发布

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本文介绍了一种利用clock()函数来测量用户函数运行时间的方法，并通过实例演示了如何将获得的时间差转换为小时、分钟和秒的形式输出。

Problem: Clock

Problem Description

In order to get the run time of a user function,you can use the clock() function in time.h.Clock() use clock tick to measure time,which will increase CLK_TCK per second.Before a user function runs,you can call clock() and get the current tick C1,and after it finishes,call clock again and get another tick C2.Then the tot time the user function runs is (C2-C1)/CLK_TCK. In this problem,you can assume that CLK_TCK is 100.You should get the rum time from C1 and C2.

Input

Each line contains 2 integers C1 and C2(0<=C1

Output

Output the run time in the format of “hh:mm:ss”(hh is the hour,mm is the minute,ss is the second,each one should be two decimal places).Please note that less than one second of time should be rounded(四舍五入) to seconds.

Sample Input

123 4577973
0 49

Sample Output

12:42:59
00:00:00

思考：本题很简单
           四舍五入的方法，将总数 +0.5 之后进行相除便会得到四舍五入的结果

代码：
#include<stdio.h>
int main()
{
    long long c1,c2;
    while(scanf("%lld %lld",&c1,&c2)!=EOF)
    {
        int sum=(c2-c1+50)/100;
        int a = sum/3600;
        int b = (sum-(a*3600))/60;
        int c = sum %60;
        printf("%02d:%02d:%02d\n",a,b,c);
    }
    return 0;
}