Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
Have you thought about this?
Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer, then the reverse of 1000000003 overflows. How should you handle such cases?
Throw an exception? Good, but what if throwing an exception is not an option? You would then have to re-design the function (ie, add an extra parameter).
public class Solution {
public int reverse(int x) {
int r = 0;
while(x != 0) {
r = r*10 + x%10;
x /= 10;
}
return r;
}
}
本文探讨了如何通过编程实现整数反转的功能,包括处理边界条件如溢出和末尾为0的情况,并提供了完整的代码示例。
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