关于c++多继承成员函数名冲突的解决方案及调用实质比较

源代码

#include <iostream>

using namespace std;
class Dog
{
        public:
                virtual void bark() { cout << "Woof!" << endl; }
                virtual void eat() { cout << "The dog has eaten." << endl; }
};



class Bird
{
        public:
                virtual void chirp() { cout << "Chirp!" << endl; }
                virtual void eat() { cout << "The bird has eaten." << endl; }
};

class DogBird : public Dog, public Bird
{
};



int main(int argc, char** argv)
{
        DogBird myConfusedAnimal;
//      myConfusedAnimal.eat(); // BUG! Ambiguous call to method eat()

        myConfusedAnimal.Dog::eat() ;
        static_cast<Dog>(myConfusedAnimal).eat() ;
}

源码分析

若直接调用myConfusedAnimal.eat()，编译错（“error: request for member ‘eat’ is ambiguous”），用两种方法明确指定具体类成员函数，分别是子类成员函数确定方法和超类确定转换方法。