/**
* Definition for an interval.
* public class Interval {
* int start;
* int end;
* Interval() { start = 0; end = 0; }
* Interval(int s, int e) { start = s; end = e; }
* }
*/
public class Solution {
public List<Interval> merge(List<Interval> intervals) {
List<Interval> res = new LinkedList<>();
if (intervals.size() == 0) {
return res;
}
Collections.sort(intervals, new Comparator<Interval>(){
@Override
public int compare(Interval a, Interval b) {
if (a.start < b.start) {
return -1;
} else if (a.start == b.start) {
return 0;
} else {
return 1;
}
}
});
Interval prev = intervals.get(0);
for (int i = 1; i < intervals.size(); i++) {
Interval interval = intervals.get(i);
if (prev.end < interval.start) {
res.add(prev);
prev = interval;
} else {
Interval newInterval = new Interval(prev.start, Math.max(prev.end, interval.end));
prev = newInterval;
}
}
res.add(prev);
return res;
}
}Merge Intervals
最新推荐文章于 2024-01-11 13:27:32 发布
本文介绍了一种将重叠的区间进行合并的算法实现。通过定义区间类并使用比较器对区间进行排序,然后遍历区间列表来合并重叠部分。该算法适用于日程安排冲突检查等场景。
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