const arr1 = [1, 2, 3, 4, 5]
const arr2 = [
{ name: '张三', age: 20, id: 1},
{ name: '李四', age: 20, id: 2},
{ name: '王五', age: 18, id: 3},
{ name: '赵六', age: 19, id: 4},
{ name: '钱七', age: 18, id: 5},
{ name: '孙八', age: 19, id: 6},
{ name: '李九', age: 20, id: 7}
]
const result1 = arr1.reduce((prev, curr) => prev + curr)
const result2 = arr2.reduce((prev, curr) => prev + curr.age, 0)
const result3 = arr2.reduce((prev, curr) => {
const index = prev.findIndex(v => v.age === curr.age)
if (index >= 0) {
prev[index].list.push(curr)
} else {
prev.push({
age: curr.age,
list: [curr]
})
}
return prev
}, [])
const result4 = arr2.reduce((prev, curr) => {
prev[curr.id] = curr
return prev
}, {})