python找出一年中的黑色星期五

def main(re_year):
leap_yrars = [] #闰年列表
for year in range(1900, re_year + 1):
if (year % 4 == 0 and year % 100 != 0) or year % 400 == 0:
leap_yrars.append(year)
week_dic = {0: “星期一”, 1: “星期二”, 2: “星期三”, 3: “星期四”, 4: “星期五”, 5: “星期六”, 6: “星期天”}
if re_year == 1900:
days = 13
else:
days = 365 * (re_year - 1900) + len(leap_yrars) + 13
result = {}
if re_year in leap_yrars: days -= 1
temp = (days - 1) % 7
result[1] = week_dic[temp]
for i in range(2, 13):
if i == 3:
if re_year in leap_yrars:
temp += 1
elif i in [5, 7, 10, 12]:
temp += 2
else:
temp += 3
if temp > 6: temp -= 7
result[i] = week_dic[temp]
if temp == 4:
print(f’{i}月13日，星期五’, end=’ ')

#调用函数输出1900-2024年的所有黑色星期五：
if name == ‘main’:
for i in range(1900, 2025): #输出1900-2024年的所有黑色星期五
print(‘\n’, f’{i}年:‘, end=’')
main(i)