MyEclipse注册机源码

最新推荐文章于 2021-03-01 16:15:14 发布

原创最新推荐文章于 2021-03-01 16:15:14 发布 · 1k 阅读

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文章标签：

#myeclipse破解码 #myeclipse注册机 #源代码 #源码 #java源码

本文介绍了一个用于生成MyEclipse许可证密钥的Java程序。该程序通过用户的用户名、版本号及授权数量等信息来生成对应的许可证密钥。密钥生成过程中还包括了日期调整、字符串格式化以及简单的加密算法。

import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.text.SimpleDateFormat;
import java.util.Calendar;

public class MyEclipseKeyGen {
public static void main(String[] args) {
String version = "300";//5.5 preview set to 511,after 5.5 set to 300
String number = "5";//license share number
String key = getSerial(System.getProperty("user.name"),version,number,true,true);
System.out.println("username="+System.getProperty("user.name"));
System.out.println("key="+key);
}

private static String getSerial(String userId, String version, String licenseNum, boolean selected, boolean proORstd)
{
Calendar cal = Calendar.getInstance();
cal.add(1, 3);
cal.add(6, -1);
NumberFormat nf = new DecimalFormat("000");
licenseNum = nf.format(Integer.valueOf(licenseNum));
String verTime = selected ?
"-" + new SimpleDateFormat("yyMMdd").format(cal.getTime()) +
"0" : "-9912310";
String type = proORstd ? "YE3MP-" : "YE2MY-";
String need = userId.substring(0, 1) +
type + version + licenseNum +
verTime;
String dx = need +
"Decompiling this copyrighted software is a violation of both your license agreement and the Digital Millenium Copyright Act of 1998 (http://www.loc.gov/copyright/legislation/dmca.pdf). Under section 1204 of the DMCA, penalties range up to a $500,000 fine or up to five years imprisonment for a first offense. Think about it; pay for a license, avoid prosecution, and feel better about yourself." +
userId;
int suf = decode(dx);
String code = need +
String.valueOf(suf);
return change(code);
}

private static int decode(String s) {
int i = 0;
char[] ac = s.toCharArray();
int j = 0;
for (int k = ac.length; j < k; j++) {
i = 31 * i + ac[j];
}
return Math.abs(i);
}

private static String change(String s) {
byte[] abyte0 = s.getBytes();
char[] ac = new char[s.length()];
int i = 0;
for (int k = abyte0.length; i < k; i++) {
int j = abyte0[i];
if ((j >= 48) && (j <= 57))
j = (j - 48 + 5) % 10 + 48;
else if ((j >= 65) && (j <= 90))
j = (j - 65 + 13) % 26 + 65;
else if ((j >= 97) && (j <= 122)) {
j = (j - 97 + 13) % 26 + 97;
}
ac[i] = ((char)j);
}
return String.valueOf(ac);
}

}