[Google Codejam] Round 1A 2016 - The Last Word

最新推荐文章于 2025-08-19 14:43:05 发布

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最新推荐文章于 2025-08-19 14:43:05 发布

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本文介绍了一种在特定游戏秀中获胜的策略，通过比较两种插入字符的方式，选择最佳方案来形成字典序最靠后的单词。使用递归思想和贪心策略确保每一步都达到全局最优解。

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[Problem Description]

Problem

On the game show The Last Word, the host begins a round by showing the contestant a string S of uppercase English letters. The contestant has a whiteboard which is initially blank. The host will then present the contestant with the letters of S, one by one, in the order in which they appear in S. When the host presents the first letter, the contestant writes it on the whiteboard; this counts as the first word in the game (even though it is only one letter long). After that, each time the host presents a letter, the contestant must write it at the beginning or the end of the word on the whiteboard before the host moves on to the next letter (or to the end of the game, if there are no more letters).

For example, for S = CAB, after writing the word C on the whiteboard, the contestant could make one of the following four sets of choices:

put the A before C to form AC, then put the B before AC to form BAC
put the A before C to form AC, then put the B after AC to form ACB
put the A after C to form CA, then put the B before CA to form BCA
put the A after C to form CA, then put the B after CA to form CAB

The word is called the last word when the contestant finishes writing all of the letters from S, under the given rules. The contestant wins the game if their last word is the last of an alphabetically sorted list of all of the possible last words that could have been produced. For the example above, the winning last word is CAB (which happens to be the same as the original word). For a game with S = JAM, the winning last word is MJA.

You are the next contestant on this show, and the host has just showed you the string S. What's the winning last word that you should produce?

Input

The first line of the input gives the number of test cases, T. T test cases follow. Each consists of one line with a string S.

Output

For each test case, output one line containing Case #x: y, where x is the test case number (starting from 1) and y is the winning last word, as described in the statement.

Limits

1 ≤ T ≤ 100.

Small dataset

1 ≤ length of S ≤ 15.

Large dataset

1 ≤ length of S ≤ 1000.

Sample

Input	Output
7 CAB JAM CODE ABAAB CABCBBABC ABCABCABC ZXCASDQWE	Case #1: CAB Case #2: MJA Case #3: OCDE Case #4: BBAAA Case #5: CCCABBBAB Case #6: CCCBAABAB Case #7: ZXCASDQWE

[Problem Analysis]

This is the first problem in this round, so it is not difficult to solve. Basically, you have to make a series of decisions each time you get a character: whether to put it before the existing word, or put it after the existing word. How to make the decision? When you think it in a recursive way(this is a powerful idea), you may found that when greedy strategy is used, the decisions will incur a global optimal solution. So you just compare the result of two different ways to insert the character, and choose the maximum value as the result, and continue to insert the next character. The solution is shown below in Python.

[Problem Solution]

    T = int(raw_input())
    for t in xrange(1, T+1):
        S = raw_input()
        res = ''
        for c in S:
            res = max(res+c, c+res)

        print 'Case #{}: {}'.format(t, res)

[Comment]

Sometimes it is important to use you instinct. Keep programming to cultivate such instinct.

[Source]

https://code.google.com/codejam/contest/4304486/dashboard