1-100之间数字中9出现的次数

#include<stdio.h>
#include <stdlib.h>
int main()
{
    int count = 0;
    int i = 0;
    for (i = 1; i <= 100; i++)
    {
        int a, b;
        a = i % 10;//个位为9
        b = i / 10;//十位为9
        if (a == 9||b == 9 )
            count++;
    }
    printf("%d\n",count);
    system("pause");
    return 0;
}