[leetcode]-58. Length of Last Word（C语言）

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World"
Output: 5

int lengthOfLastWord(char* s) {
    int i=0,j,k,l,len=strlen(s);
    if(len==0)
        return 0;
    int sum=0;
    for(i=0;i<len;i++)
    {
        if(s[i]!=' ')
            sum++;
        else
        {
            for(j=i+1;j<len;j++)
                if(s[j]==' ')
                    continue;
                else
                    break;
            if(j==len)
                return sum;
            else
            {
                i=j-1;
                sum=0;
            }
        }
    }
    return sum;
}