Problem Description
给你一串字符,不超过50个字符,可能包括括号、数字、字母、标点符号、空格,你的任务是检查这一串字符中的( ) ,[ ],{ }是否匹配。
Input
输入数据有多组,处理到文件结束。
Output
如果匹配就输出“yes”,不匹配输出“no”
Example Input
sin(20+10)
{[}]
Example Output
yes no
code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define STACK_INIT_SIZE 100
#define STACKINCREMENT 10
#define OVERLOAD -2
#define ERROR 0
#define OK 1
typedef char ElemType;
typedef struct
{
ElemType *base;
ElemType *top;
int stacksize;
}Sqstack;
void InitStack(Sqstack &s)//初始化栈
{
s.base = (ElemType *)malloc(STACK_INIT_SIZE*sizeof(ElemType));
if(!s.base)
{
exit(OVERLOAD);
}
s.top = s.base;
s.stacksize = STACK_INIT_SIZE;
}
int GetTop(Sqstack s, ElemType &e)
{
if(s.top == s.base) return ERROR;
e = *(s.top-1);
return OK;
}
void Push(Sqstack &s, ElemType e)//入栈
{
if(s.top-s.base>=s.stacksize)
{
s.base = (ElemType*)realloc(s.base, (s.stacksize+STACKINCREMENT)*sizeof(ElemType));
if(!s.base) exit(OVERLOAD);
s.top = s.base+s.stacksize;
s.stacksize+=STACKINCREMENT;
}
*s.top++ = e;
}
int Pop(Sqstack &s, ElemType &e)//出栈,并将元素赋给e
{
if(s.top == s.base) return ERROR;
e = *--s.top;
return OK;
}
int main()
{
Sqstack li;
InitStack(li);
char s[55];
int i;
char e;
while(gets(s))
{
InitStack(li);
int flag = 1;
for(i = 0;i<strlen(s);i++)
{
if(s[i] == '('||s[i] == '['||s[i] == '{')
{
Push(li, s[i]);
}
else if(s[i] == ')'||s[i] == ']'||s[i] == '}')
{
if (GetTop(li, e) == ERROR)
{
flag = 0;
break;
}
if(e==s[i]-1||e==s[i]-2)
{
Pop(li, e);
}
else
{
flag = 0;
break;
}
}
}
if(GetTop(li, e)!=ERROR) flag = 0;
if(flag) printf("yes\n");
else printf("no\n");
}
}
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