lua实现xxTea加解密

最新推荐文章于 2025-07-01 11:13:22 发布

Scruel Tao

最新推荐文章于 2025-07-01 11:13:22 发布

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CC 4.0 BY-SA版权

分类专栏：算法文章标签： lua 函数解密

本文链接：https://blog.youkuaiyun.com/scruelt/article/details/52711498

还是直接上代码吧~


function _long2str(v, w)
    local len = #v


    local n = bit.lshift((len - 1) , 2)
    if (w) then
        local m = v [len]
        if ((m < n - 3) or (m > n)) then
        return false
        end
        n = m
    end
    local s = {}
    for i = 1 , len do
        s [i] = string.packL(v[i])
    end


    if (w) then
        return string.sub(table.concat(s, ''), 0, n)
    else
        return table.concat(s, '')
    end
end
function _str2long(s, w)
    local v = string.unpackL(s .. string.rep("\0", (4 - bit.band((string.len(s) % 4)  , 3))))
    if (w) then
        v [#v+1] = string.len(s)
    end
    return v
end
function _int32(n)
    while (n >= 2147483649) do
        n = n - 4294967296
    end
    while (n <= -2147483649) do
        n = n + 4294967296
    end
    return n
end





function security.xxTEAEncrypt(str, key, toBase64)


    toBase64 = toBase64 or true
    if (str == "") then
        return ""
    end
    local v = _str2long(str, true)
    local k = _str2long(key, false