psql FATAL role vagrant does not exist

文章详细介绍了在使用Vagrant进行环境搭建时遇到的PostgreSQL角色不存在错误的解决方法,包括虚拟机安装、Vagrant包安装、配置及最终问题排查过程。通过创建与当前用户对应的PostgreSQL角色或使用默认的postgres用户,成功解决了安装过程中的障碍。

I have been trying to set up vagrant but I am getting this error. I will list out my installation method. Please suggest changes where you feel they are needed.

-Installed virtual box
sudo apt-get install virtual box

-Downloaded .deb package from vagrant website

-Installed it using
sudo dpkg -i (package_name)

-then I selected the vagrant folder in the fullstack folder and
vagrant up
vagrant ssh

then I did :
vagrant@vagrant-ubuntu-trusty-32: cd /vagrant/forumvagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$ sudo apt-get install postgresql-client-commonvagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$ sudo apt-get install postgres-xc-client

Then finally:
vagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$ psqlpsql: FATAL: role "vagrant" does not exist

share improve this question
 
 
Sure, you haven't set up a Postgres role that corresponds to your current user (which is vagrant). postgresql.org/docs/9.3/static/user-manag.html –  Oliver Charlesworth  May 24 '15 at 13:09 

4 Answers

1)First exit the vagrant prompt 

exit

2) Halt the vagrant instance

vagrant halt

3)Destroy the vagrant instance 

vagrant destroy

4)Create a new instance 

vagrant up

This might solve it. It atleast did for me.(Tried it)

share improve this answer
 

This is happening because there is no role specified in postgres. When there is no role specified, it tries to use the username of the account as the default role and hence your error. So, now, you could either create a role in postgres for the vagrant user or just use the postgres user itself. So, first, login with the postgres user:

psql -U postgres

then, create a role for the user vagrant

CREATE ROLE vagrant LOGIN;

In case, if you want it with a password, use:

CREATE USER vagrant WITH PASSWORD 'password';

or

CREATE ROLE vagrant WITH LOGIN PASSWORD 'password';

CREATE USER is the same as CREATE ROLE with the exception that USER implies LOGIN.

Source

share improve this answer
 
 
vagrant@vagrant-ubuntu-trusty-32:/$ psql -U postgres psql: could not connect to server: No such file or directory Is the server running locally and accepting connections on Unix domain socket "/var/run/postgresql/.s.PGSQL.5432"? vagrant@vagrant-ubuntu-trusty-32:/$  –  Siddhant Loya  May 24 '15 at 13:32 
 
try 'sudo service postgres restart' –  Siddharth Shukla  May 24 '15 at 13:41
 
postgres: unrecognized service –  Siddhant Loya  May 24 '15 at 13:48
 
sudo apt-get update; sudo apt-get install postgresql postgresql-contrib; and then repeat the steps in the answer. Looks like a postgres installation issue. –  Siddharth Shukla  May 24 '15 at 13:59 
 
After I run psql -U postgres it gives this error:  psql: could not connect to server: No such file or directory Is the server running locally and accepting connections on Unix domain socket "/var/run/postgresql/.s.PGSQL.5432"? –  Siddhant Loya  May 25 '15 at 4:51 

You need to change to the postgres user and give vagrant superuser access.

sudo su - postgres
createuser vagrant -s
exit  # exit from postgres user back into vagrant

You can do everything with with vagrant now.

share improve this answer
 

You are trying to connect to postgresql using vagrant user. In this case, postgresql y looking for the corresponding vagrant role (if not specified, the default role for a user is it's username). However, looks like there is no such role created.

You can create the role, or try for example a login using the postgres user:

vagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$ psql -U postgres

You can also specify the databasename you want to connect to:

vagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$ psql -U postgres -d DATABASENAME
share improve this answer
 
 
-bash: vagrant@vagrant-ubuntu-trusty-32:/vagrant/forum$: No such file or directory –  Siddhant Loya  May 24 '15 at 13:26
 
That's the path specified in the question. Simply try to type psql the command: psql -U postgres -d DATABASENAME –  Federico Cristina  May 24 '15 at 13:29
### 解决 Postgres PSQL 迁移后出现 'relation does not exist' 错误 在将 PostgreSQL 数据库从 Windows 迁移到 Linux 后,使用 `psql` 时出现的 `'relation does not exist'` 错误通常与以下几个方面有关:数据库对象未正确迁移、模式(schema)问题或权限设置错误。 #### 1. 确认数据库对象是否完整迁移 如果在迁移过程中某些表或视图未被正确导出或导入,可能会导致 `'relation does not exist'` 错误。确保在导出和导入过程中使用了正确的命令[^1]。 - 在 Windows 环境中导出数据库时,可以使用以下命令: ```bash pg_dump -U 用户名 -d 数据库名 -f 备份文件.sql ``` - 在 Linux 环境中恢复数据库时,使用以下命令: ```bash psql -U 用户名 -d 新数据库名 -f 备份文件.sql ``` 确认备份文件是否包含所有需要的表和视图。如果某些对象缺失,可能需要重新执行导出和导入操作。 #### 2. 检查模式(Schema)设置 PostgreSQL 默认使用 `public` 模式存储表和其他数据库对象。如果在迁移过程中更改了模式,或者目标数据库未正确应用模式,则可能导致 `'relation does not exist'` 错误。 - 使用以下查询检查当前数据库中的模式: ```sql SELECT schema_name FROM information_schema.schemata; ``` - 确保在导入数据时指定了正确的模式。例如,在导入 SQL 文件时,可以添加 `-n` 参数指定模式: ```bash psql -U 用户名 -d 新数据库名 -f 备份文件.sql -n public ``` 如果迁移的数据库使用了自定义模式,需确保目标数据库中已创建相应的模式,并在导入时正确映射这些模式。 #### 3. 验证权限设置 即使对象已成功迁移,如果用户没有适当的权限访问这些对象,也可能导致 `'relation does not exist'` 错误。验证用户的权限设置: - 检查用户对特定表的权限: ```sql \z 表名 ``` - 如果权限不足,可以授予必要的权限: ```sql GRANT SELECT, INSERT, UPDATE, DELETE ON ALL TABLES IN SCHEMA public TO 用户名; ``` #### 4. 确认字符编码和排序规则一致性 如果源数据库和目标数据库的字符编码或排序规则不一致,可能导致对象名称解析失败。确保两个环境的配置一致: - 检查数据库的编码和排序规则: ```sql SHOW lc_collate; SHOW client_encoding; ``` - 如果发现不一致,可以在创建目标数据库时指定匹配的参数: ```bash createdb -U 用户名 -E UTF8 --locale=en_US.UTF-8 新数据库名 ``` #### 5. 验证函数和触发器 如果数据库中包含自定义函数或触发器,且这些对象未正确迁移或语法不兼容,也可能引发 `'relation does not exist'` 错误。确保所有函数和触发器已被正确导入并测试其功能[^2]。 - 检查函数是否存在: ```sql SELECT routine_name FROM information_schema.routines WHERE specific_schema = 'public'; ``` - 如果发现缺失的函数,将其脚本重新导入到目标数据库。 #### 示例代码 以下是一个完整的示例,展示如何验证和修复 `'relation does not exist'` 错误: ```sql -- 检查表是否存在 SELECT * FROM information_schema.tables WHERE table_name = 'example_table'; -- 如果表不存在,尝试重新导入 \! psql -U 用户名 -d 新数据库名 -f 备份文件.sql -- 检查用户权限 \z example_table -- 授予权限 GRANT SELECT, INSERT, UPDATE, DELETE ON example_table TO 用户名; -- 检查模式设置 SELECT schema_name FROM information_schema.schemata; -- 设置搜索路径以包含正确的模式 SET search_path TO public, custom_schema; ``` ###
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