You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take the first turn to remove the stones.
Both of you are very clever and have optimal strategies for the game. Write a function to determine whether you can win the game given the number of stones in the heap.
For example, if there are 4 stones in the heap, then you will never win the game: no matter 1, 2, or 3 stones you remove, the last stone will always be removed by your friend.
Hint:
- If there are 5 stones in the heap, could you figure out a way to remove the stones such that you will always be the winner?
public boolean canWinNim(int n) {
if(n%4 == 0) return false;
else return true;
}

本文介绍了一种Nim游戏的胜负策略。在这个游戏中,玩家轮流从一堆石头中取走1到3块,取走最后一块石头的人获胜。文章提供了一个简洁的函数,用于判断在给定石头数量的情况下是否能赢得游戏。
399

被折叠的 条评论
为什么被折叠?



