Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactlyL characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.
Return the formatted lines as:
[ "This is an", "example of text", "justification. " ]
Note: Each word is guaranteed not to exceed L in length.
- A line other than the last line might contain only one word. What should you do in this case?
- In this case, that line should be left-justified.
Analysis:
Not complicated in algorithm. It focused on implement.
1. count line word number & index
2. calculate interval space (average and extra space)
3. construct line string with word and space. there be difference between last line and other lines
4. record each line to result.
Java
public List<String> fullJustify(String[] words, int L) {
List<String> result = new ArrayList<>();
int len = words.length;
if(len<=0) return result;
int i = 0;
while(i<len){
int start = i;//start index
int sum = 0;//level length
while(i<len && sum+words[i].length()<=L){
sum+=words[i].length()+1;
i++;
}
int end = i-1;//end index
int intervalCount = end-start;//interval number
int avgSp = 0, leftSp = 0;
if(intervalCount>0){
avgSp = (L-sum+intervalCount+1)/intervalCount;
leftSp = (L-sum+intervalCount+1)%intervalCount;
}
StringBuffer line = new StringBuffer();
for(int j = start;j<end;j++){//construct line char
line.append(words[j]);
if(i==len)
line.append(' ');
else {
int temp = avgSp;
while(temp>0){
line.append(' ');
temp--;
}
if(leftSp>0){
line.append(' ');
leftSp--;
}
}
}
line.append(words[end]);
while(line.length()<L){
line.append(' ');
}
result.add(line.toString());
}
return result;
}
c++
vector<string> fullJustify(vector<string> &words, int L) {
vector<string> result;
if(0==words.size()) return result;
int i=0;
while(i<words.size()){
int start =i;
int sum=0;
while(i<words.size() && sum+words[i].size()<=L){
sum+=words[i].size()+1;
i++;
}
int end = i-1;
int intervalCount = end-start;//interval space between words, "abc 1 bcd 2 def"
int avgSp = 0, leftSp = 0;
if(intervalCount >0){
avgSp = (L-sum+intervalCount+1)/intervalCount;
leftSp = (L-sum+intervalCount+1)%intervalCount;
}
string line;// construct new line
for(int j=start; j<end;j++){
line += words[j];
if(i == words.size())// the last line
line.append(1,' ');
else{
line.append(avgSp,' ');//average space
if(leftSp>0){//extra space
line.append(1,' ');
leftSp--;
}
}
}
line+=words[end];// add last word
if(line.size()<L)
line.append(L-line.size(),' ');
result.push_back(line);
}
return result;
}

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