条款12：复制对象时勿忘其每一个成分

#include<iostream>
#include<string>
using namespace std;
void logCall(const string&funcName){};
class Date{};
class Base{
public:
	//....
	Base(){}
	Base(const Base&rhs){
		logCall("A::copy constructor");
	}
	Base&operator=(const Base&rhs){
		logCall("A::copy assignment operator");
		name = rhs.name;
		return *this;
	}
private:
	string name;
	Date d;
};
class Derived :public Base{
public:
	//..
	Derived(){}
	Derived(const Derived&rhs):Base(rhs)/*这里如果不写会调用默认，但会报错*/,m_i(rhs.m_i){
		logCall("Derived::copy constructor");
	}
	/*Derived&operator=(const Derived&rhs){
		logCall("Derived::copy assignment operator");
		Base::operator=(rhs);//这里也要对基类部分进行拷贝赋值 因为无法访问基类的私有成员变量
		m_i = rhs.m_i;
		return *this;
	}*/
	Derived &operator=(const Derived &rhs){
		logCall("Derived::copy assignment operator");
		if (this != &rhs){
			static_cast<Base&>(*this) = rhs;
		}
		return *this;
	}
private:
	int m_i;
};