/*这道题一直RE,果然数组开小了,key word最长可以有70个字符,坑爹啊,没看清题*/
/*思路就是开了一个二维数组 然后3循环暴力搜索,简单的字符串匹配,没什么技巧,而且题上说每个keyword前后都有非字母,所以判断的时候也很好判断*/
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main()
{
int num[75];
char temp[75];
char key[30][75];
char excuse[30][75];
int i, j, k, N, K, t, max, cout;
cout = 0;
while( scanf( "%d%d", &N, &K ) != EOF )
{
getchar();
memset( num, 0, sizeof(num) );
for( i = 0; i < N; i++ )
gets( key[i] );
for( i = 0; i < K; i++ )
gets( excuse[i] );
t = 0;
for( i = 0; i < N; i++ )
for( j = 0; j < K; j++ )
for( k = 0; k < strlen(excuse[j]); k++ )
{
if( isalpha(excuse[j][k]) )
temp[t++] = tolower(excuse[j][k]);
else
{
temp[t] = '\0';
if( !strcmp(temp, key[i]) )
num[j]++;
t = 0;
}
}
max = 1;
for( i = 0; i < K; i++ )
if( num[i] >= max )
max = num[i];
printf( "Excuse Set #%d\n", ++cout );
for( i = 0; i < K; i++ )
if( num[i] == max )
printf( "%s\n", excuse[i] );
printf( "\n" );
}
return 0;
}
UVA 409
最新推荐文章于 2021-08-04 15:15:41 发布