移动温度荷载计算

本文探讨了在工程领域中如何计算移动温度荷载对结构的影响,作者XuJC详细阐述了相关理论和方法。

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 /com, units: SI, m - degree C - W - kg -sec - J 
Bi=h*dx/K = 60*0.002/51.9 = 0.0023 < 1 
F0 = ( Kdt ) / (rho*C*dx^2) 
assume F0= beta = 0.4 
dt = (beta*rho*C*dx^2)/K = 0.1179 (sec) 
 
/title,transient analysis 2 (moving heat flux) 
/filnam,transient-2 
/triad,rbot 
/prep7 
wpstyle,,,,,,,,1 
wpstyle,0.01,0.01,0,0.1,0.003,0,1,,5 
blc4,0,0.1,0.1,-0.1 !0.1*0.1 m 
cyl4,0.03,0.05,0.01 
asba, 1, 2 !drill a hole 
blc4,0.1,0.1,-0.01,-0.1 
flst,2,2,5,orde,2 
fitem,2,1 
fitem,2,3 
aovlap,p51x 
wpstyle,,,,,,,,0 
aplot 
et,1,plane55 
keyopt,1,1,0 
keyopt,1,3,0 !2d plane problem 
keyopt,1,4,0 
keyopt,1,8,0 295 
keyopt,1,9,0 
aisi 1045 steel 
uimp,1,dens, , ,7870 , !kg/m3 
uimp,1,kxx, , , 51.9 , !w/m-c 
uimp,1,c, , , 486, !w-s / kg-c 
type,1 
mat,1 
esize,0.002, !element size = 0.002 m 
mshkey,1 
amesh,1 
mshkey,0 
amesh,2 
!boundary conditions 
/psf,hflu, ,2,0 
convection 
flst,2,1,4,orde,1 
fitem,2,4 
sfl,p51x,conv,50, ,25, 
finish 
/solu 
antype,trans 
trnopt,full 
nropt
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